s^2-24s-25=0

Solution for s^2-24s-25=0 equation:

s^2-24s-25=0

a = 1; b = -24; c = -25;
Δ = b2-4ac
Δ = -242-4·1·(-25)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-26}{2*1}=\frac{-2}{2}
=-1
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+26}{2*1}=\frac{50}{2}
=25
$